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6a^2-b (y + z)a= 1, b=-1, y=1, z=0

6a^2-b (y + z)a= 1, b=-1, y=1, z=0

Asked by: Guest | Views: 208
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Guest [Entry]

"a = 1
b = -1
y = 1
z = 0

6a^2 - b(y + z)

= 6(1)^2 - (-1)(1 + 0)
= 6 + 1
= 7"